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If we compare the emission spectrum of a hydrogen atom (or other chemical element) detected in a terrestrial laboratory, with that of an atom of the same element belonging to an astronomical source S, at R distance from the Earth, we notice that between the two spectra there is a frequency shift. The most significant observation of modern astronomy is the so-called cosmological redshift. Lunar Laser Ranging Experiment, Dilation of Light Curves of Supernovae Ia, Redshift, Hubble’s Law, Dark Matter, Abnormal Acceleration, Acceleration of Expansion of Universe 5) The dilation of the light curves observed for supernovae Ia. 4) The peripheral motion of stars in galaxies around their rotational centre. 3) The high redshift of supernovae Ia, which seems to evidence an acceleration of the expansion of the universe. 2) The anomalous acceleration a p ≈ −8 × 10 −10 m∙sec −2, measured for some spacecrafts. Results: Under the hypothesis c time varying, we explain: 1) The cosmological redshift. Methods: The paper links the variation dc/dt with the Hubble constant and infers a value of dc/dt from the difference between the value of the variation of the Earth-Moon distance measured by the Lunar Laser Ranging Experiment and the tidal effect. In this way the problems of the tired hypothesis are overcome. In the hypothesis of the author the speed c, during this journey, is assumed constant. This hypothesis differs from the so-called tired light, in which the velocity c is supposed to vary during the journey of photons in the empty space for some frictional mechanism. Received: FebruAccepted: MaPublished: March 12, 2019Īims: The paper explores the hypothesis that the speed of light c is decreasing over time at rate #Acceleration due to gravity lab physics 411 licenseThis work is licensed under the Creative Commons Attribution International License (CC BY 4.0). Instead of the acceleration being 9.81 m/s^2 as I hypothesized, it was actually 6.73 m/s^2 when calculated due to calculation and experimental errors.Technical High School, ITIS Malignani, Udine, ItalyĬopyright © 2019 by author(s) and Scientific Research Publishing Inc. My hypothesis was only partially correct. I concluded that the velocity-time graph did go in a straight line. ![]() A random error that occurred was that one group member released the object, not in synchronization with the ticker timer which may have hindered the process of dots being recorded on the tape. The anticipated error was that the numbers would have been rounded and not completely accurate.Īnother systematic error is that the ruler is not 100% accurate when measuring it may be off by. One error might be in the calculations in Table 1. ErrorsĪfter performing the experiment, several errors were noted. We know that velocity changes with t = time and displacement changes with v = velocity. Given the formula vf = vi +at and d = (vf +vi/2). ![]() Due to a change in velocity, there was a change in displacement. This was because as time increases, velocity changed at a constant rate. #Acceleration due to gravity lab physics 411 freeThe change in velocity of an object in free fall was directly proportional to the displacement. The velocity position graph (refer to graph 2) was curved because changing velocity means change in slope.ĥ. The slope of the velocity time graph was accelerating 6.74 m/s^2. The relationship between the change in velocity and elapsed time was that the velocity increases constantly as the time increases therefore they were proportionate.ģ. It was heading in a positive direction (refer to graph 1).Ģ. The velocity-time graph is in a straight line, meaning it was going at a constant acceleration. Therefore the acceleration throughout was 6.74 m/s^2 this may be caused by experimental errors and calculation errors.ġ. = 674 cm/s^2 (*note: To convert into meters, I divided (674 cm/s^2) by 100) Therefore at 0.2s, the average velocity was 92cm/s.Īcceleration was found by finding the slope of the velocity time graph. To find average velocity I did the following: One example calculation would be at 0.2 seconds, when displacement is 9.2cm. Position from the start (cm)Īverage velocity was found by dividing change in time by displacement. I measured and recorded the position from the start of the tape corresponding to each half time interval and then plotted a velocity-position graph using the velocities I recorded. ![]() I calculated the slope of the velocity-time graph, which gave me acceleration in cm/s^2. ![]()
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